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php调用JAVA类时出现以下错误？
php调用JAVA类时出现以下错误？
地址 http://down.shanxihu.com/dotest.php
Fatal error: Uncaught [o(Exception):"java.lang.Exception: Invoke failed: [o(crypt)]->encryptDecryptStr(o(PhpParserString), o(PhpParserString)). Cause: java.lang.NoSuchMethodException: encryptDecryptStr(o(PhpParserString), o(PhpParserString)). Candidates: [] Responsible VM: 1.5.0_05@http://java.sun.com/" at: #-5 php.java.bridge.JavaBridge.Invoke(JavaBridge.java:1086) #-4 php.java.bridge.Request.handleRequest(Request.java:342) #-3 php.java.bridge.Request.handleRequests(Request.java:388) #0 [internal function]: Java->__call('encryptDecryptS...', Array) #1 /usr/local/apache/htdocs/down/dotest.php(4): Java->encryptDecryptStr('abc', '55678') #2 {main}] thrown in /usr/local/apache/htdocs/down/dotest.php on line 4
JAVA类代码 复制PHP内容到剪贴板
PHP代码:
<?php
import java.io.IOException;
import java.io.UnsupportedEncodingException;
import sun.misc.BASE64Decoder;
import sun.misc.BASE64Encoder;
public class crypt {
//加密方法
private static String encryptDecryptStr(String p, String key)
{ //把要加密的字符串p转换为Stringbuffer 以便进行插入操作
StringBuffer pstrb=new StringBuffer();
for(int j=0;j<p.length();j++)
{
pstrb.append(p.substring(j, j+1));
}
//按照一定规则把key的值插入到要加密的字符串中
pstrb=pstrb.insert(pstrb.length()/2, "-"+key.substring(0,key.length()/2));
p=pstrb.insert(pstrb.length(), "+"+key.substring(key.length()/2)).toString();
try {
byte[] bs=p.getBytes("gb2312");
byte[] keys=key.getBytes("gb2312");
for(int i=0;i<bs.length;i++)
{
bs[i]=(byte)(bs[i]^ keys[i%keys.length]);
}
StringBuilder sb=new StringBuilder();
for (byte by : bs)
{
sb.append(by+",");
}
byte []pb=(sb.toString().substring(0, (sb.toString().length()-1))).getBytes("gb2312");
//利用加密算法对字符串进行加密
p=new BASE64Encoder().encode(pb);
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return p;
}
?> PHP调用代码 复制PHP内容到剪贴板
PHP代码:
<?php
java_require( '/usr/local/lib/php/extensions/no-debug-non-zts-20060613/' );
$new = new java('crypt');
$content =$new->encryptDecryptStr("abc", "55678");
echo $content;
?>
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