cator
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注册 2006-10-10
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[推荐阅读] 让JS点击后再执行？一个按钮，两个onclick,请问如何加？
临时写了个函数, 没做深入调试, LZ自己测试一下
<?php
function checkIt($number) {
$modes = array( 'AAAABBBB', 'AABBCCDD', 'ABABCDCD', 'AAABAAAB', 'AABBAABB', 'ABCDABCD',
'AAAAAA', 'ABCDEFG',
'AAAAAA', 'ABBABB', 'AAAABB', 'AAABBB', 'AABBCC', 'ABABAB', 'ABCABC',
'AAAAA', 'AABBB', 'AAAAB', 'AAABB',
'AAAA', 'ABAB', 'AABB', 'ABBA', 'AAAB', '####'/*升降序*/,
'AAA', '###'/*升降序*/,
'AA' ); //前后排序有优先级,只要有一个匹配,后面的就不再检索了
$result = 'unknown';
foreach ($modes as $mode) {
$len = strlen($mode);
$s = substr($number, -$len);
$temp = array();
$match = true;
for ($i=0; $i<$len; $i++) {
if ($mode[$i]=='#') {
if (!isset($temp['step'])) {
$temp['step'] = 0;
$temp['current'] = intval($s[$i]);
} elseif ($temp['step'] == 0) {
$temp['step'] = $temp['current'] - intval($s[$i]);
if ($temp['step'] != -1 && $temp['step'] != 1) {
$match = false;
break;
} else {
$temp['current'] = intval($s[$i]);
}
} else {
$step = $temp['current'] - intval($s[$i]);
if ($step != $temp['step']) {
$match = false;
break;
} else {
$temp['current'] = intval($s[$i]);
}
}
} else {
if (isset($temp[$mode[$i]])) {
if ($s[$i] != $temp[$mode[$i]]) {
$match = false;
break;
}
} else {
$temp[$mode[$i]] = $s[$i];
}
}
}
if ($match) {
$result = $mode;
break;
}
}
return $result;
}
echo checkIt('13888888888');
?>
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