liuqh
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注册 2004-9-1
来自 beijing php
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xajax问题,the XML response that was returned from the server is invalid;
试用了一下xAjax，有点问题，不知道如何解决，请高手指点。
出错提示：the XML response that was returned from the server is invalid;
代码如下：
require('xajax/xajax.inc.php'); // 外部引用;
function showInfo($selectID)
{
$conn=mysql_connect("localhost","root","");
$sql="SELECT id,title FROM news_article WHERE sortid=7 LIMIT 0,10";
$result=mysql_db_query("biotech",$sql);
while($arr=mysql_fetch_array($result))
{
$zt1.="<a href=http://localhost/news/news/show.php?id=".$arr['id'].">".$arr['title']."</a><BR>";
}
echo $zt1;
$zt1=iconv("GB2312", "UTF-8",$zt1);
$objResponse=new xajaxResponse();
$objResponse->addAssign($selectID,"innerHTML",$zt1);
return $objResponse;
}
$xajax=new xajax();
$xajax->registerFunction("showInfo");
$xajax->processRequests();
?>
<html>
<head>
<meta HTTP-EQUIV="content-type" CONTENT="text/html; charset=UTF-8">
<title>Xajax试用</title>
<?php $xajax->printJavascript();?>
</head>
<body>
测试Xajax<!--读出数据库-->生成动态表格。
<input type="button" onclick="<?php echo "xajax_showInfo('zt1')"; ?>" value="专题报道一">
<span id="zt1" width="35%"></span>
<BR>
<span id="zt2" width="35%"></span>
</body>
</html> [ 本帖最后由 liuqh 于 2006-8-25 05:46 PM 编辑 ]
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